PW Crack 4

Link to the exercise

This one is basically the same as pw-crack-3, the only difference is the possible passwords count.

Steps ​

PW Crack 3 was proposing a valid password among 6 non-valid ones. This exercise gives 100 options to validate instead.

I could go over each of them, but it wouldn't be feasible. Instead, I modified the function I created before to print out the hashes to print only the password that's hash is the same as correct_pw_hash.

for p in pos_pw_list:
	if (hash_pw(p) == correct_pw_hash):
		print(p)

I seriously wonder why I didn't take the same route when doing PW Crack 3. I'm starting to like Python...

Flag ​

picoCTF{fl45h_5pr1ng1ng_ae0fb77c}